If $a_{1} = a^{2} = 2,\ a_{n} = a_{n - 1} - 1(n 2),\ then\ a_{5}$ is

Question

If $a_{1} = a^{2} = 2,\ a_{n} = a_{n - 1} - 1(n > 2),\ then\ a_{5}$ is

Dr. Abubacker · Accepted Answer

(b)
Given that, $a_{1} = a_{2} = 2$ and $a_{n} = a_{n - 1} - 1$
$	herefore\ a_{3} = a_{2} - 1 = 2 - 1 = 1$
$a_{4} = a_{3} - 1 = 1 - 1 = 0$
$a_{5} = a_{4} - 1 = 0 - 1 = - 1$

Q. If $a_{1} = a^{2} = 2,\ a_{n} = a_{n - 1} - 1(n > 2),\ then\ a_{5}$ is

Explanation

Reviewed by Dr. Abubacker

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