(b) Since, $ar^{4} = 2$ $\therefore\ a \times ar \times ar^{2} \times ar^{3} \times ar^{4} \times ar^{5} \times ar^{6} \times ar^{7} \times ar^{8}$ $= a^{9}r^{36} = \left( ar^{4} \right)^{9} = 2^{9} = 512$
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Ph.D. in Physics with 19+ years of teaching experience.