Q. If $a,\ b,\ c,\ d,\ e,\ f\$ are in AP, then the value of $e - c$ will be
A) 2$(c - a)$
B) 2$(f - d)$
C) 2$(d - c)$
D) $d - c$
Explanation
(c)
Since, $a,\ b,\ c,\ d,\ e,\ f$ are in AP.
So, $b - a = c - b = d - c = e - d = f - e = k$
Where $k$ is the common difference
Now, $d - c = e - d\ \Rightarrow e + c = 2d$
$\Rightarrow e - c + 2c = 2d\ \Rightarrow e - c = 2(d - c)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.