Q. In the expansion of $2\log_{e}x - \log_{e}{(x + 1)} - \log_{e}{(x - 1)}$ the coefficient of $x^{- 4}$ is

A) $\frac{1}{2}$
B) $- 1$
C) 1
D) None of these
Explanation

(a)
$2\log_{e}x - \log_{e}\left\{ \left( 1 + \frac{1}{x} \right)x \right\} - \log_{e}\left\{ \left( 1 - \frac{1}{x} \right)x \right\}$
$= 2\log_{e}x - \left\{ \log_{e}\left( 1 + \frac{1}{x} \right) + \log_{e}x \right\} - \left\{ \log_{e}\left( 1 - \frac{1}{x} \right) + \log_{e}x \right\}$
$= - \left\{ \log_{e}\left( 1 + \frac{1}{x} \right) + \log_{e}\left( 1 - \frac{1}{x} \right) \right\} = 2\left\lbrack \frac{1}{2x^{2}} + \frac{1}{4x^{4}} + ... \right\}$
$\therefore$ The coefficients of $x^{- 4} = 2 \times \frac{1}{4} = \frac{1}{2}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.