Q. Three numbers are in AP such that their sum is 18 and sum of their squares is 158. The greatest number among them is

A) 10
B) 11
C) 12
D) None of these
Explanation

(b)
Let the three numbers $(a - d),a$ and $(a + d)$ are in AP. Then,
$(a - d) + a + (a + d) = 18\ \ \ \Rightarrow a = 6$ …(i)
and $(a - d)^{2} + a^{2} + (a + d)^{2} = 158$
$\Rightarrow 3a^{2} + 2d^{2} = 158$
$\Rightarrow 2d^{2} = 158 - 3 \times 36$ [from Eq. (i)]
$\Rightarrow \ d = \pm 5$
Hence, the required numbers are 1, 6, 11 or 11, 6, 1
Thus, greatest number is 11.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.