Q. The sum of the series $6 + 66 + 666 + ...$ upto $n$ term is

A) $\frac{10^{n - 1} - 9n + 10}{81}$
B) $\frac{{2(10}^{n + 1} - 9n - 10)}{27}$
C) $\frac{{2(10}^{n} - 9n - 10)}{27}$
D) None of these
Explanation

(b)
Let $S = 6 + 66 + 666 + ...n$ terms
$= \frac{6}{9}(9 + 99 + 999 + ...n$ terms)
$= \frac{2}{3}\lbrack(10 - 1) + (100 - 1) + (1000 - 1) + ...n$ terms]
$= \frac{2}{3}\left\lbrack 10 \bullet \frac{{(10}^{n} - 1)}{9} - n \right\rbrack = \frac{2}{27}\lbrack 10^{n + 1} - 10 - 9n\rbrack$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.