Q. The sum of 10 terms of the series $\sqrt{2} + \sqrt{6} + \sqrt{18} + ...$ is
A) $121\left( \sqrt{6} + \sqrt{2} \right)$
B) $243\left( \sqrt{3} + 1 \right)$
C) $\frac{121}{\sqrt{3} - 1}$
D) $242\left( \sqrt{3} - 1 \right)$
Explanation
The correct answer is Option A: $121\left( \sqrt{6} + \sqrt{2} \right)$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.