Q. The bisector of the acute angle formed between the lines $4x - 3y + 7 = 0$ and $3x - 4y + 14 = 0$ has the equation
A) $x + y + 3 = 0$
B) $x - y - 3 = 0$
C) $x - y + 3 = 0$
D) $3x + y - 7 = 0$
Explanation
(c)
Here, $a_{1}a_{2} + b_{1}b_{2} = (4 \times 3 + 3 \times 4) = 24 > 0$
$\therefore$ The equation of the bisector is
$\frac{4x - 3y + 7}{5} = \pm \frac{3x - 4y + 14}{5}$
Talking negative sign.
$x - y + 3 = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.