Q. If the bisectors of angles represented by $ax^{2} + 2hxy + {by}^{2} = 0$ and $a^{'}x^{2} + 2h^{'}xy + b^{'}y^{2} = 0$ are same, then
A) $(a - b)h^{'} = \left( a^{'} - b^{'} \right)h$
B) $(a - b)h = \left( a^{'} - b^{'} \right)h'$
C) $(a + b)h^{'} = \left( a^{'} - b^{'} \right)h$
D) $(a - b)h^{'} = \left( a^{'} + b^{'} \right)h$
Explanation
(a)
Since, bisector are same, therefore
$\frac{a - b}{h} = \frac{a^{'} - b'}{h'}$
$\Rightarrow \ (a - b)h^{'} = \left( a^{'} - b^{'} \right)h$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.