Q. The equation of the line equidistant from the lines $2x + 3y + 5 = 0$ and $4x + 6y = 11$ is
A) $2x + 3y - 1 = 0$
B) $4x + 6y - 1 = 0$
C) $8x + 12y - 1 = 0$
D) None of these
Explanation
(c)
Since, the lines $2x + 3y + 5 = 0$ and $2x + 3y - \frac{11}{2} = 0$ are parallel
Let required line is $2x + 3y + \lambda = 0$
$\therefore\ \lambda = \frac{5 - \frac{11}{2}}{2} = - \frac{1}{4}$
So, $8x + 12y - 1 = 0$ is the required line
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.