Q. If the line $px - qy = r$ intersects the coordinate axes at $(a,\ 0)$ and $(0,\ b)$, thyen the value of $a + b$ is equal to
A) $r\left( \frac{q + p}{pq} \right)$
B) $r\left( \frac{q - p}{pq} \right)$
C) $r\left( \frac{p - q}{pq} \right)$
D) $r\left( \frac{p + q}{p - q} \right)$
Explanation
(b)
Points $(a,\ 0)$ and $(0,\ b)$ will satisfy the equation of line $px - qy = r$
$\Rightarrow ap = r,\ - bq = r$
$\therefore a + b = \frac{r}{p} - \frac{r}{q} = r\left( \frac{q - p}{pq} \right)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.