If the lines $x = a + m,\ y = - 2\$and $y = mx$ are concurrent, then least value of $|a|$ is

Question

Dr. Abubacker · Accepted Answer

(c)
From the given equations, we get
$m^{2} + am + 2 = 0$
Since, $m$ is real, $a^{2} \geq 8\  \Rightarrow |a| \geq 2\sqrt{2}$
So, least value of $|a|$ is $2\sqrt{2}$

Q. If the lines $x = a + m,\ y = - 2\$and $y = mx$ are concurrent, then least value of $|a|$ is

Explanation

Reviewed by Dr. Abubacker

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