(d) $Required\ distance = \left| \frac{65 + 39}{\sqrt{25 + 144}} \right|\ \ \ \ \ \ \ \ \left\lbrack \because d = \frac{\left| c_{1} - c_{2} \right|}{\sqrt{a^{2} + b^{2}}} \right\rbrack$ $= \left| \frac{104}{13} \right| = 8\ unit$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.