Q. Separate equations of lines for a pair of lines whose equation is $x^{2} + xy - 12y^{2} = 0$, are
A) $x + 4y = 0$ and $x + 3y = 0$
B) $2x - 3y = 0$ and $x - 4y = 0$
C) $x - 6y = 0$ and $x - 3y = 0$
D) $x + 4y = 0$ and $x - 3y = 0$
Explanation
(d)
Given equation can be rewritten as
$x^{2} + 4xy - 3xy - 12y^{2} = 0$
Factorising the above equation, we get
$(x + 4y)(x - 3y) = 0$
Therefore, separate equations for the lines are
$x + 4y = 0\ and\ x - 3y = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.