Q. If the lines $kx - 2y - 1 = 0$ and $6x - 4y - m = 2$ are identical (coincident ) lines, then the values of $k$ and $m$ are

A) $k = 3,\ m = 2$
B) $k = - 3,\ m = 2$
C) $k = - 3,\ m = - 2$
D) $k = 3,\ m = - 2$
Explanation

(a)
Given lines are $kx - 2y - 1 = 0$
and $6x - 4y - m = 0$
Since, these lines are coincident.
$\therefore\ \frac{k}{6} = \frac{- 2}{- 4} = \frac{- 1}{- m}$
$\Rightarrow \frac{k}{6} = \frac{1}{2}$ and $\frac{1}{m} = \frac{1}{2}$
$\Rightarrow k = 3$ and $m = 2$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.