Explanation

(c)
(1)Let $A$ and $B$ be the points where the lines $2x + 3y + 19 = 0$ meets the coordinates axes and let $C$ and $O$ be the points where the line $9x + 6y - 17 = 0\$meet the coordinate axes
$Then,\ OA = \frac{19}{2},\ OB = \frac{19}{2},$
$OC = \frac{17}{9}\ and\ OD = \frac{17}{6}$
Thus, the segments $AOC$ and $BOD$ intersect at such that $OA \bullet OC = OB \bullet OD.$ Hence, $A,\ B,\ C,\ D$ are concyclic
(2) Distance of $(2,\ - 5)$ from the line $3x + y + 5 - 0$ is
$\frac{2 \times 3 - 5 + 5}{\sqrt{3^{2} + 1^{2}}} = \frac{6}{\sqrt{10}}$
and distance of $( - 1,\ 4)$ from the line $3x + y + 5 = 0$ is
$\frac{3( - 1) + 4 + 5}{\sqrt{10}} = \frac{6}{\sqrt{10}}$
Thus, the points are equidistant from the given line
Hence, both of these statements are correct