Explanation

(c)
Given sides of a triangle are $x - 3\ y = 0,\ 4x + 3y = 5$ and $3x + y = 0$
Since, the lines $x - 3y = 0$ and $3x + y = 0$ are perpendicular to each other, therefore it is right angled triangle and the point of intersection (0, 0) is the orthocentre of a triangle.
$\therefore$ The line $3x - 4y = 0$ is passes through origin (0, 0) $ie$, it is passes through orthocentre.