Q. The equation of the straight line perpendicular to $5x - 2y = 7$ and passing through the point of intersection of the lines $2x + 3y = 1$ and $3x + 4y = 6$, is
A) $2x + 5y + 17 = 0$
B) $2x + 5y - 17 = 0$
C) $2x - 5y + 17 = 0$
D) $2x - 5y = 17$
Explanation
(a)
Let the equation of line which is perpendicular to $5x - 2y = 7$, is
$2x + 5y = \lambda$ …(i)
The point of intersection of given lines is $(14,\ - 9)$
Since, the Eq. (i) is passing through the point $(14,\ - 9)$
$\therefore\ 2(14) + 5( - 9) = \lambda\ \Rightarrow \ \lambda = - 17$
$\therefore$ Eq. (i) becomes
$2x + 5y + 17 = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.