If $a
eq b
eq c$ and if $ax + by + c = 0,\ bx + cy + a = 0,\ \ cx + ay + b = 0$ are concurrent, then $2^{a^{2_{b} - 1_{c} - 1}} \bullet 2^{b^{2_{c} - 1_{b} - 1}} \bullet 2^{c^{2_{a} - 1_{b} - 1}}$ is equal to

Question

If $a 
eq b 
eq c$ and if $ax + by + c = 0,\ bx + cy + a = 0,\ \ cx + ay + b = 0$ are concurrent, then $2^{a^{2_{b} - 1_{c} - 1}} \bullet 2^{b^{2_{c} - 1_{b} - 1}} \bullet 2^{c^{2_{a} - 1_{b} - 1}}$ is equal to

Dr. Abubacker · Accepted Answer

The correct answer is Option A: 8.

Q. If $a \neq b \neq c$ and if $ax + by + c = 0,\ bx + cy + a = 0,\ \ cx + ay + b = 0$ are concurrent, then $2^{a^{2_{b} - 1_{c} - 1}} \bullet 2^{b^{2_{c} - 1_{b} - 1}} \bullet 2^{c^{2_{a} - 1_{b} - 1}}$ is equal to

Explanation

Reviewed by Dr. Abubacker

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