Q. The angle between the lines $\sqrt{3}x - y - 2 = 0$ and $x - \sqrt{3}y + 1 = 0$ is
A) $90{^\circ}$
B) $60{^\circ}$
C) $45{^\circ}$
D) $30{^\circ}$
Explanation
(d)
$Slopes\ of\ given\ lines\ are\ m_{1} = \sqrt{3}\ and\ m_{2} = \frac{1}{\sqrt{3}}$
$\therefore\ \tan{\theta =}\left| \frac{\sqrt{3} - \frac{1}{\sqrt{3}}}{1 + 1} \right| = \left| \frac{3 - 1}{2\sqrt{3}} \right| = \frac{1}{\sqrt{3}}$
$\Rightarrow \ \theta = 30{^\circ}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.