Q. The equation $y = \pm \sqrt{3}x,\ y = 1$ are the sides of
A) An equilateral triangle
B) A right angled triangle
C) An isosceles triangle
D) An obtuse triangle
Explanation
(a)
Equation of $OA$ is $y = \sqrt{3}x$. Equation of $OB$ is $y = - \sqrt{3}x$ and equation of $AB$ is $y = 1$
[image:10_image24.emf]
Clearly, from figure $\mathrm{\Delta}OAB$ is an equilateral triangle.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.