Q. A line $AB$ makes zero intercepts on $x$-axis and $y$-axis and it is perpendicular to another line $CD$ which is $3x + 4y + 6 = 0$. The equation of line $AB$ is
A) $y = 4$
B) $4x - 3y + 8 = 0$
C) $4x - 3y = 0$
D) $4x - 3y + 6 = 0$
Explanation
(c)
Given line $AB$ makes 0 intercepts on $x$-axis and $y$-aixs or $\left( x_{1},\ y_{1} \right) \equiv (0,\ 0)$ and the line is perpendicular to line $CD,\ 3x + 4y + 6 = 0$
$\therefore$ Slope of required line which is perpendicular $3x + 4y + 6 = 0$ is $4/3$
$\therefore$ Required line which is passing through origin and having slope 4/3, is
$y - 0 = \frac{4}{3}(x - 0)$
$\Rightarrow \ 4x - 3y = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.