Q. A straight line through $P(1,2)$ is such that its intercept between the axes is bisected at $P$. Its equation is

A) $x + y = - 1$
B) $x + y = 3$
C) $x + 2y = 5$
D) $2x + y = 4$
Explanation

(d)
∵ $P(1,\ 2)$ is mid point of $AB$, therefore coordinate of $A$ and $B$ respectively (2, 0) and (0,4).
$\therefore$ Equation of line $AB$ is
$y - 0 = \frac{4}{- 2}(x - 2)\ \Rightarrow \ 2x + y = 4$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.