Q. The equation of the straight line which is perpendicular to $y = x$ and passes through (3, 2) is
A) $x - y = 5$
B) $x + y = 5$
C) $x + y = 1$
D) $x - y = 1$
Explanation
(b)
∵ Slope of given line $y = x$ is 1
$\therefore$ Slope of required line which is perpendicular to given line is $- 1$
Thus, the equation of required line passing through (3, 2) and slope $- 1$, is
$y - 2 = - 1(x - 3)$
$\Rightarrow \ \ x + y = 5$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.