Q. A straight line through the point $A(3,4)$ is such that its intercept between the axes is bisected at $A$. Its equation is
A) $3x - 4y + 7 = 0$
B) $4x + 3y = 24$
C) $3x + 4y = 25$
D) $x + y = 7$
Explanation
(b)
Since, $A$ is mid point of line $P\mathcal{Q}$
$\therefore\ 3 = \frac{a + 0}{2} = a = 6$
and $4 = \frac{0 + b}{2}\ \Rightarrow \ b = 8$
Thus, equation of line is
$\frac{x}{6} + \frac{y}{8} = 1\ \Rightarrow \ 4x + 3y = 24$
[image:10_image28.emf]
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.