Q. The point of concurrence of the lines $ax + by + c = 0$ and $a,\ b,\ c$ satisfy the relation $3a + 2b + 4c = 0$ is
A) $\left( \frac{3}{2},\frac{1}{4} \right)$
B) $\left( \frac{3}{4},\frac{1}{4} \right)$
C) $\left( \frac{3}{4},\frac{1}{2} \right)$
D) $\left( \frac{3}{2},\frac{1}{2} \right)$
Explanation
(c)
Given lines are $ax + by + c = 0$ …(i)
and $a,\ b,\ c$ satisfy the relation
$3a + 2b + 4c = 0$ …(ii)
Only option (c) satisfy both condition.
$\because a \bullet \frac{3}{4} + b \bullet \frac{1}{2} + c = 0$
$\Rightarrow 3a + 2b + 4c = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.