Q. The straight line whose sum of the intercepts on the axes is equal to half to the product of the intercepts, passes through the point whose coordinates are
A) (1, 1)
B) (2, 2)
C) (3, 3)
D) (4, 4)
Explanation
(b)
Let $a$ and $b$ the intercepts made by the straight line on the axes
$Given\ that,\ a + b = \frac{ab}{2}$
$\Rightarrow \frac{2a + 2b}{ab} = 1\ \Rightarrow \frac{2}{a} + \frac{2}{b} = 1$
On comparing with $\frac{x}{a} + \frac{y}{b} = 1,$ we get
$x = 2,\ y = 2$
$\therefore\$ Required point is (2, 2)
So, the straight line passes through the point (2, 2)
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.