If one of the lines of ${my}^{2} + \left( 1 - m^{2} \right)xy - {mx}^{2} = 0$ is a bisector of the angle between the lines $xy = 0$, then $m$ is/are

Question

Dr. Abubacker · Accepted Answer

(c)
Equation of bisectors of lines $xy = 0\ are\ y = \pm x.$
Put $y = \pm x$ in $my^{2} + \left( 1 - m^{2} \right)xy - {mx}^{2} = 0,\$we get
${mx}^{2} \pm \left( 1 - m^{2} \right)x^{2} - {mx}^{2} = 0$
$\Rightarrow \ \left( 1 - m^{2} \right)x^{2} = 0\  \Rightarrow \ m = \pm 1$

Q. If one of the lines of ${my}^{2} + \left( 1 - m^{2} \right)xy - {mx}^{2} = 0$ is a bisector of the angle between the lines $xy = 0$, then $m$ is/are

Explanation

Reviewed by Dr. Abubacker

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