Q. The vertices of $\mathrm{\Delta}OBC$ are (0, 0), $( - 3,\ - 1)$ and $( - 1,\ - 3)$, then the equation of the line parallel to $BC$ which is a distance $\frac{1}{2}$ from the origin and cut $OB$ and $OC$ intercept, is
A) $2x - 2y + \sqrt{2} = 0$
B) $2x + 2y + \sqrt{2} = 0$
C) $2x + 2y - \sqrt{2} = 0$
D) $x + y\sqrt{2} = 0$
Explanation
The correct answer is Option B: $2x + 2y + \sqrt{2} = 0$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.