Q. Three straight lines $2x + 11y - 5 = 0,\ 24x + 7y - 20 = 0$ and $4x - 3y - 2 = 0$

A) From a triangle
B) Are only concurrent
C) Are concurrent with one line bisecting the angle between the other two
D) None of the above
Explanation

(c)
For the two lines $24x + 7y - 20 = 0$ and $4x - 3y - 2 = 0,$ the angle bisectors are
$given\ by\frac{24x + 7y - 20}{25} = \pm \frac{4x - 3y - 2}{5}$
Talking positive sign, we get
$2x + 11y - 5 = 0$
$\therefore$ The given three lines are concurrent with one line bisecting the angle between the other two.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.