(c)
For the two lines $24x + 7y - 20 = 0$ and $4x - 3y - 2 = 0,$ the angle bisectors are
$given\ by\frac{24x + 7y - 20}{25} = \pm \frac{4x - 3y - 2}{5}$
Talking positive sign, we get
$2x + 11y - 5 = 0$
$\therefore$ The given three lines are concurrent with one line bisecting the angle between the other two.