(b) Slope of the given lines are $m_{1} = \frac{2 + 2}{3 - 1} = 2\ and\ m_{2} = - \frac{1}{2}$ $Now,\ \ \ m_{1} \times m_{2} = 2 \times \frac{- 1}{2} = - 1$ $\therefore$ Lines are perpendicular, so angle is $\frac{\pi}{2}$
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