Q. The bisector of the acute angle formed between the lines $4x - 3y + 7 = 0$ and $3x - 4y + 14 = 0$ has the equation
A) $x + y + 3 = 0$
B) $x - y - 3 = 0$
C) $x - y + 3 = 0$
D) $3x + y - 7 = 0$
Explanation
(c)
The equation of bisector of acute angle formed between the lines $4x - 3y + 7 = 0\ at\ 3x - 4y + 14 = 0,\$is
$\frac{4x - 3y + 7}{\sqrt{16 + 9}}$
$= - \frac{3x - 4y + 14}{\sqrt{16 + 9}}$
$\Rightarrow \ 7x - 7y + 21 = 0$
$\Rightarrow \ x - y + 3 = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.