Q. A straight line through $P(1,\ 2)$ is such that intercept between the axes is bisected at $P$. Its equation is
A) $x + y = - 1$
B) $x + y = 3$
C) $x + 2y = 5$
D) $2x + y = 4$
Explanation
(d)
Since, $P(1,\ 2)$ is mid point of $AB$. Therefore, coordinate of $A$ and $B$ are (2, 0) and (0, 4) respectively
[image:10_image38.emf]
$\therefore\$Equation of line $AB$ is
$y - 0 = \frac{4}{- 2}(x - 2)$
$\Rightarrow \ 2x + y = 4$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.