Q. If 3, 4 are intercepts of a line $L \equiv 0,$ then the distance of $L \equiv 0$ from the origin is
A) 5 units
B) 12 units
C) $\frac{5}{12}\$unit
D) $\frac{12}{5}$ unit
Explanation
(d)
$Equation\ of\ line\ is\ \frac{x}{3} + \frac{y}{4} = 1$
$\Rightarrow \ 4x + 3y - 12 = 0$
$Now,\ distance\ from\ origin = \left| \frac{4 \times 0 + 3 \times 0 - 12}{\sqrt{3^{2} + 4^{2}}} \right| = \frac{12}{5}\ units$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.