Q. The equation of the bisector of the acute angle between the lines $3x - 4y + 7 = 0$ and $12x + 5y - 2 = 0$ is

A) $99x - 27y - 81 = 0$
B) $11x - 3y + 9 = 0$
C) $21x + 77y - 101 = 0$
D) $21x + 77y + 101 = 0$
Explanation

(c)
$\because a_{1}a_{2} + b_{1}b_{2} = 3(12) + ( - 4)(5) = 16 > 0$
$\therefore$ The equation of bisector of the acute angle between these lines are
$\frac{3x - 4y + 7}{\sqrt{3^{2} + 4^{2}}} = \frac{12x + 5y - 2}{\sqrt{12^{2} + 5^{2}}}$
$\Rightarrow \ 13(3x - 4y + 7) = 5(12x + 5y - 2)$
$\Rightarrow \ 21x + 77y - 101 = 0$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.