Q. Consider the following statements: If $\left| \begin{matrix} x_{1} & y_{1} & 1 \\ x_{2} & y_{2} & 1 \\ x_{3} & y_{3} & 1 \end{matrix} \right| = \left| \begin{matrix} a_{1} & b_{1} & 1 \\ a_{2} & b_{2} & 1 \\ a_{3} & b_{3} & 1 \end{matrix} \right|,\$then the two triangles with vertices $\left( x_{1},\ y_{1} \right),\ \left( x_{2},\ y_{2} \right),\ (x_{3},\ y_{3})$ and $\left( a_{1},\ b_{1} \right),\ \left( a_{2},\ b_{2} \right),\ (a_{3},\ b_{3})$ must be congruent Only one straight line can be drown through the origin at equal distance from the points $A(2,\ 2)$ and $B(4,\ 0)$ Which of these is/are correct

A) Only 1
B) Only 2
C) Both of these
D) None of these
Explanation

(d)
(1) We have, $\left| \begin{matrix}
x_{1} & y_{1} & 1 \\
x_{2} & y_{2} & 1 \\
x_{3} & y_{3} & 1
\end{matrix} \right| = \left| \begin{matrix}
a_{1} & b_{1} & 1 \\
a_{2} & b_{2} & 1 \\
a_{3} & b_{3} & 1
\end{matrix} \right|$
This shows that the area of both the triangles are same. But the equality of the areas of the triangles do not ensure the congruence of the triangle
(2) The equation of a line passing through the origin is $y = mx$. If it is equidistant from the points $A(2,\ 2)$ and $B(4,\ 0)$, then
$\left| \frac{2m - 2}{\sqrt{m^{2} + 1}} \right| = \left| \frac{4m - 0}{\sqrt{m^{2} + 1}} \right|$
$\Rightarrow (2m - {2)}^{2} = ({4m)}^{2}$
$\Rightarrow (m - {1)}^{2} = {4m}^{2}$
$\Rightarrow \ {3m}^{2} + 2m - 1 = 0$
$\Rightarrow m = \frac{1}{3},\ - 1$
Hence, there are two lines $y = \frac{x}{3}$ and $y = - x$ passing through the origin and equidistance from $A(2,\ 2)$ and $B(4,\ 0)$
Hence, both of these two statements are not correct

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.