Q. A line has slope $m$ and $y$-intercept 4. The distance between the origin and the line is equal to
A) $\frac{4}{\sqrt{1 - m^{2}}}$
B) $\frac{4}{\sqrt{m^{2} - 1}}$
C) $\frac{4}{\sqrt{m^{2} + 1}}$
D) $\frac{4m}{\sqrt{1 + m^{2}}}$
Explanation
(c)
Equation of line is
$y = mx + 4$
$\therefore Required\ distance = \frac{4}{\sqrt{1 + m^{2}}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.