Q. If ${ax}^{2} - y^{2} + 4x - y = 0$ represents a pair of lines, then $a$ is equal to

A) $- 16$
B) $16$
C) 4
D) $- 4$
Explanation

(b)
Here, $a = a,\ h = 0,\ b = - 1,\ f = - \frac{1}{2},\ g = 2,\ c = 0$
Given equation represent a pair of straight line.
$Then,\ \left| \begin{matrix}
a & 0 & 2 \\
0 & - 1 & - 1/2 \\
2 & - 1/2 & 0
\end{matrix} \right| = 0$
$\Rightarrow \ a\left\lbrack 0 - \left( \frac{1}{4} \right) \right\rbrack - 0 + 2\lbrack 2\rbrack = 0\ \ \Rightarrow \ a = 16$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.