Q. The equation of bisectors of the angles between the lines $|x| = |y|$ are

A) $y = \pm x$ and $x = 0$
B) $x = \frac{1}{2}$ and $y = \frac{1}{2}$
C) $y = 0$ and $x = 0$
D) None of these
Explanation

(c)
The equation of lines are $\pm x \pm y = 0.$ Now, we take the lines $x + y = 0$ and $x - y = 0.$
$\therefore$ The equation of bisector of the angles between these lines are
$\frac{x + y}{\sqrt{1 + 1}} = \pm \frac{x - y}{\sqrt{1 + 1}}$
$\Rightarrow x + y = \pm (x - y)$
Taking positive sign, $x + y = x - y\ \Rightarrow y = 0$
Taking negative sign, $x + y = - (x - y) \Rightarrow x = 0$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.