(a)
On solving $3x + 4y = 9$ and $y = mx + 1,\$ we get
$x = \frac{5}{3 + 4m}$
$\because x$ is an integer
$\therefore 3 + 4m = 1,\ - 1,\ 5,\ - 5$
$\Rightarrow m = \frac{- 2}{4},\frac{- 4}{4},\frac{2}{4},\frac{- 8}{4}$
So, $m$ has two integral values