Q. The point of intersection of tangents at the ends of the latusrectum of the parabola $y^{2} = 4x$, is equal to
A) (1,0)
B) $( - 1,0)$
C) (0, 1)
D) $(0,\ - 1)$
Explanation
(b)
The coordinates at the ends of the latusrectum of the parabola $y^{2} = 4x$ are $L(1,2)$ and $L_{1}(1 - 2)$
Equation of tangent at $L$ and $l_{1}\ are\ 2y = 2(x + 1)$ and $- 2y = 2(x + 1)$, which gives $x = - 1,\ y = 0$
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.