Explanation

(a)
The equation of ellipse can be rewritten as
$\frac{(x + 1)^{2}}{9} + \frac{(y - 2)^{2}}{5} = 1$
$\therefore\ e = \sqrt{1 - \frac{5}{9}} = \frac{2}{3}\ \ \ \ \lbrack\because a > b\rbrack$
Foci are $\left\{ \left( - 1 \pm 3.\frac{2}{3} \right),2 \right\} ie,\ (1,2)$ and$\ ( - 3,\ 2)$