Q. The equation of the smallest circle passing through the points (2, 2) and (3, 3) is

A) $x^{2} + y^{2} + 5x + 5y + 12 = 0$
B) $x^{2} + y^{2} - 5x - 5y + 12 = 0$
C) $x^{2} + y^{2} + 5x - 5y + 12 = 0$
D) $x^{2} + y^{2} - 5x + 5y - 12 = 0$
Explanation

(b)
Let the points be $A = (2,\ 2)$and$B = (3,\ 3)$. Since the circle passing through these points, so they satisfy the equation of the circle.
Now, taking option (b),
Let $S \equiv x^{2} + y^{2} - 5x - 5y + 12 = 0$
At $A\text{=}(2,\ 2)$
$2^{2} + 2^{2} - 5(2) - 5(2) + 12 = 0$
At $B = (3,\ 3)$
$3^{2} + 3^{3} - 5(3) - 5(3) + 12 = 0$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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