Q. The difference in focal distances of any point on the hyperbola $\frac{x^{2}}{16} - \frac{y^{2}}{9} = 1$ is
A) 8
B) 9
C) 0
D) 6
Explanation
(a)
Given, $\frac{x^{2}}{16} - \frac{y^{2}}{9} = 1$
We know that the difference of focal distances of any point of the hyperbola is equal to major axis
$\therefore$ Required distance$= 2a = 2 \times 4 = 8$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.