(c) The given equation of parabola is $x^{2} - 4x - 8y + 12 = 0$ $\Rightarrow x^{2} - 4x = 8y - 12$ $\Rightarrow x^{2} - 4x + 4 = 8y - 12 + 4$ $\Rightarrow {(x - 2)}^{2} = 8(y - 1)$ $\therefore$ The length of latusrectum $= 4a = 8$
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