(a)
Let $P(x,y)$ be any point on the parabola. By definition of parabola $PM = PS$
$\frac{x + 2y - 1}{\sqrt{1 + 4}} = \sqrt{(x - 1)^{2} + y^{2}}$
$\Rightarrow \ x^{2} + 4y^{2} + 1 + 4xy - 4y - 2x = 5\left( x^{2} + 1 - 2x + y^{2} \right)$
$\Rightarrow \ 4x^{2} + y^{2} - 8x + 4y - 4xy + 4 = 0$