Q. The area of the circle whose centre is at (2, 3) and passing through (4, 6), is
A) $5\pi\ sq\ units$
B) $10\pi\ sq\ units$
C) $13\pi\ sq\ units$
D) None of these
Explanation
(c)
Here, $r = \sqrt{(4 - 2)^{2} + (6 - 3)^{2}} = 13$
$\therefore$ area of circle$= \pi r^{2} = \pi \times 13 = 13\pi$ sq units
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.