Q. The eccentricity of the ellipse $9x^{2} + 5y^{2} - 30y = 0\$is
A) 1/3
B) 2/3
C) 3/4
D) 4/5
Explanation
(b)
Given equation can be rewritten as
$\frac{x^{2}}{5} + \frac{(y - 3)^{2}}{9} = 1$
$\therefore\ e = \sqrt{1 - \frac{a^{2}}{b^{2}}} = \sqrt{1 - \frac{5}{9}}$
$\Rightarrow \ e = \frac{2}{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.