Q. Radius of circle in which a chord length $\sqrt{2}$ makes an angle $\frac{\pi}{2}$ at the centre, is
A) 1
B) $\sqrt{3}$
C) $\frac{\sqrt{3}}{2}$
D) None of these
Explanation
(a)
In $\mathrm{\Delta}ADB,\ AD = \frac{1}{\sqrt{2}}\ cosec\ 45{^\circ} = 1$
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.