Q. The equation of circle is$x^{2} + y^{2} - 2x = 0$. The point $P( - 1,\ 0)$ lies
A) On the circle
B) Inside the circle
C) Outside the circle
D) On the centre of the circle
Explanation
(c)
Let $S = x^{2} + y^{2} - 2x$
At $P( - 1,\ 0),\ S_{1} = ( - 1)^{2} + 0 - 2( - 1) = 3 > 0$
This point $P( - 1,\ 0)$ lies outside the circle
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.